Distance from Secaucus to Wittenberge
The shortest distance (air line) between Secaucus and Wittenberge is 3,889.72 mi (6,259.90 km).
How far is Secaucus from Wittenberge
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 16:30 (21.08.2025)
Wittenberge is located in Prignitz, Germany within 53° 0' 0" N 11° 45' 0" E (53.0000, 11.7500) coordinates. The local time in Wittenberge is 22:30 (21.08.2025)
The calculated flying distance from Wittenberge to Wittenberge is 3,889.72 miles which is equal to 6,259.90 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Wittenberge, Prignitz, Germany