Distance from Secaucus to Waddinxveen
The shortest distance (air line) between Secaucus and Waddinxveen is 3,640.29 mi (5,858.49 km).
How far is Secaucus from Waddinxveen
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 11:13 (11.11.2025)
Waddinxveen is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 39' 0" E (52.0500, 4.6500) coordinates. The local time in Waddinxveen is 17:13 (11.11.2025)
The calculated flying distance from Waddinxveen to Waddinxveen is 3,640.29 miles which is equal to 5,858.49 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Waddinxveen, Oost-Zuid-Holland, Netherlands