Distance from Secaucus to Waalwijk
The shortest distance (air line) between Secaucus and Waalwijk is 3,666.04 mi (5,899.93 km).
How far is Secaucus from Waalwijk
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 11:12 (11.11.2025)
Waalwijk is located in Midden-Noord-Brabant, Netherlands within 51° 40' 59.88" N 5° 4' 0.12" E (51.6833, 5.0667) coordinates. The local time in Waalwijk is 17:12 (11.11.2025)
The calculated flying distance from Waalwijk to Waalwijk is 3,666.04 miles which is equal to 5,899.93 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Waalwijk, Midden-Noord-Brabant, Netherlands