Distance from Secaucus to Veenendaal
The shortest distance (air line) between Secaucus and Veenendaal is 3,676.78 mi (5,917.20 km).
How far is Secaucus from Veenendaal
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 18:52 (11.11.2025)
Veenendaal is located in Utrecht, Netherlands within 52° 1' 0.12" N 5° 32' 60" E (52.0167, 5.5500) coordinates. The local time in Veenendaal is 00:52 (12.11.2025)
The calculated flying distance from Veenendaal to Veenendaal is 3,676.78 miles which is equal to 5,917.20 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Veenendaal, Utrecht, Netherlands