Distance from Secaucus to Tomaszow Mazowiecki
The shortest distance (air line) between Secaucus and Tomaszow Mazowiecki is 4,246.59 mi (6,834.22 km).
How far is Secaucus from Tomaszow Mazowiecki
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 05:56 (13.11.2025)
Tomaszow Mazowiecki is located in Piotrkowski, Poland within 51° 31' 0.12" N 20° 1' 0.12" E (51.5167, 20.0167) coordinates. The local time in Tomaszow Mazowiecki is 11:56 (13.11.2025)
The calculated flying distance from Tomaszow Mazowiecki to Tomaszow Mazowiecki is 4,246.59 miles which is equal to 6,834.22 km.
Secaucus, New Jersey, United States
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Tomaszow Mazowiecki, Piotrkowski, Poland