Distance from Secaucus to Sint Anthonis
The shortest distance (air line) between Secaucus and Sint Anthonis is 3,699.94 mi (5,954.47 km).
How far is Secaucus from Sint Anthonis
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 22:43 (11.11.2025)
Sint Anthonis is located in Noordoost-Noord-Brabant, Netherlands within 51° 37' 32.88" N 5° 52' 51.96" E (51.6258, 5.8811) coordinates. The local time in Sint Anthonis is 04:43 (12.11.2025)
The calculated flying distance from Sint Anthonis to Sint Anthonis is 3,699.94 miles which is equal to 5,954.47 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Sint Anthonis, Noordoost-Noord-Brabant, Netherlands