Distance from Secaucus to Simpelveld
The shortest distance (air line) between Secaucus and Simpelveld is 3,724.84 mi (5,994.55 km).
How far is Secaucus from Simpelveld
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 05:51 (12.11.2025)
Simpelveld is located in Zuid-Limburg, Netherlands within 50° 49' 59.88" N 5° 58' 59.88" E (50.8333, 5.9833) coordinates. The local time in Simpelveld is 11:51 (12.11.2025)
The calculated flying distance from Simpelveld to Simpelveld is 3,724.84 miles which is equal to 5,994.55 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Simpelveld, Zuid-Limburg, Netherlands