Distance from Secaucus to Sentrupert
The shortest distance (air line) between Secaucus and Sentrupert is 4,248.05 mi (6,836.57 km).
How far is Secaucus from Sentrupert
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 15:21 (17.11.2025)
Sentrupert is located in Jugovzhodna Slovenija, Slovenia within 45° 58' 36.84" N 15° 5' 22.92" E (45.9769, 15.0897) coordinates. The local time in Sentrupert is 21:21 (17.11.2025)
The calculated flying distance from Sentrupert to Sentrupert is 4,248.05 miles which is equal to 6,836.57 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Sentrupert, Jugovzhodna Slovenija, Slovenia