Distance from Secaucus to Scherpenzeel
The shortest distance (air line) between Secaucus and Scherpenzeel is 3,671.80 mi (5,909.18 km).
How far is Secaucus from Scherpenzeel
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 05:52 (11.11.2025)
Scherpenzeel is located in Veluwe, Netherlands within 52° 4' 59.88" N 5° 28' 0.12" E (52.0833, 5.4667) coordinates. The local time in Scherpenzeel is 11:52 (11.11.2025)
The calculated flying distance from Scherpenzeel to Scherpenzeel is 3,671.80 miles which is equal to 5,909.18 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Scherpenzeel, Veluwe, Netherlands