Distance from Secaucus to San Severino Marche
The shortest distance (air line) between Secaucus and San Severino Marche is 4,263.89 mi (6,862.06 km).
How far is Secaucus from San Severino Marche
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 23:36 (30.08.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 05:36 (31.08.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,263.89 miles which is equal to 6,862.06 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
San Severino Marche, Macerata, Italy