Distance from Secaucus to San Pietro in Casale
The shortest distance (air line) between Secaucus and San Pietro in Casale is 4,136.52 mi (6,657.09 km).
How far is Secaucus from San Pietro in Casale
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:35 (30.08.2025)
San Pietro in Casale is located in Bologna, Italy within 44° 42' 0" N 11° 24' 0" E (44.7000, 11.4000) coordinates. The local time in San Pietro in Casale is 16:35 (30.08.2025)
The calculated flying distance from San Pietro in Casale to San Pietro in Casale is 4,136.52 miles which is equal to 6,657.09 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
San Pietro in Casale, Bologna, Italy