Distance from Secaucus to Rotterdam
The shortest distance (air line) between Secaucus and Rotterdam is 3,637.63 mi (5,854.20 km).
How far is Secaucus from Rotterdam
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 11:06 (11.11.2025)
Rotterdam is located in Groot-Rijnmond, Netherlands within 51° 55' 0.12" N 4° 30' 0" E (51.9167, 4.5000) coordinates. The local time in Rotterdam is 17:06 (11.11.2025)
The calculated flying distance from Rotterdam to Rotterdam is 3,637.63 miles which is equal to 5,854.20 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Rotterdam, Groot-Rijnmond, Netherlands