Distance from Secaucus to Petershagen
The shortest distance (air line) between Secaucus and Petershagen is 3,800.75 mi (6,116.72 km).
How far is Secaucus from Petershagen
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 14:38 (20.08.2025)
Petershagen is located in Minden-Lübbecke, Germany within 52° 22' 59.88" N 8° 58' 0.12" E (52.3833, 8.9667) coordinates. The local time in Petershagen is 20:38 (20.08.2025)
The calculated flying distance from Petershagen to Petershagen is 3,800.75 miles which is equal to 6,116.72 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Petershagen, Minden-Lübbecke, Germany