Distance from Secaucus to Panevezys
The shortest distance (air line) between Secaucus and Panevezys is 4,248.16 mi (6,836.76 km).
How far is Secaucus from Panevezys
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:16 (05.09.2025)
Panevezys is located in Panevėžio apskritis, Lithuania within 55° 43' 59.88" N 24° 21' 0" E (55.7333, 24.3500) coordinates. The local time in Panevezys is 17:16 (05.09.2025)
The calculated flying distance from Panevezys to Panevezys is 4,248.16 miles which is equal to 6,836.76 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Panevezys, Panevėžio apskritis, Lithuania