Distance from Secaucus to Oudenburg
The shortest distance (air line) between Secaucus and Oudenburg is 3,595.37 mi (5,786.19 km).
How far is Secaucus from Oudenburg
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 09:34 (01.08.2025)
Oudenburg is located in Arr. Oostende, Belgium within 51° 10' 59.88" N 3° 0' 0" E (51.1833, 3.0000) coordinates. The local time in Oudenburg is 15:34 (01.08.2025)
The calculated flying distance from Oudenburg to Oudenburg is 3,595.37 miles which is equal to 5,786.19 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Oudenburg, Arr. Oostende, Belgium