Distance from Secaucus to Miedzyrzecz
The shortest distance (air line) between Secaucus and Miedzyrzecz is 4,050.67 mi (6,518.93 km).
How far is Secaucus from Miedzyrzecz
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 17:36 (12.11.2025)
Miedzyrzecz is located in Gorzowski, Poland within 52° 26' 53.88" N 15° 35' 17.88" E (52.4483, 15.5883) coordinates. The local time in Miedzyrzecz is 23:36 (12.11.2025)
The calculated flying distance from Miedzyrzecz to Miedzyrzecz is 4,050.67 miles which is equal to 6,518.93 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Miedzyrzecz, Gorzowski, Poland