Distance from Secaucus to Lukovica
The shortest distance (air line) between Secaucus and Lukovica is 4,224.79 mi (6,799.14 km).
How far is Secaucus from Lukovica
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 20:42 (15.11.2025)
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 02:42 (16.11.2025)
The calculated flying distance from Lukovica to Lukovica is 4,224.79 miles which is equal to 6,799.14 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Lukovica, Osrednjeslovenska, Slovenia