Distance from Secaucus to Lidzbark Warminski
The shortest distance (air line) between Secaucus and Lidzbark Warminski is 4,176.47 mi (6,721.38 km).
How far is Secaucus from Lidzbark Warminski
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:09 (12.11.2025)
Lidzbark Warminski is located in Olsztyński, Poland within 54° 7' 0.12" N 20° 34' 59.88" E (54.1167, 20.5833) coordinates. The local time in Lidzbark Warminski is 16:09 (12.11.2025)
The calculated flying distance from Lidzbark Warminski to Lidzbark Warminski is 4,176.47 miles which is equal to 6,721.38 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Lidzbark Warminski, Olsztyński, Poland