Distance from Secaucus to Leopoldsburg
The shortest distance (air line) between Secaucus and Leopoldsburg is 3,688.12 mi (5,935.46 km).
How far is Secaucus from Leopoldsburg
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 12:29 (31.07.2025)
Leopoldsburg is located in Arr. Hasselt, Belgium within 51° 7' 0.84" N 5° 15' 20.88" E (51.1169, 5.2558) coordinates. The local time in Leopoldsburg is 18:29 (31.07.2025)
The calculated flying distance from Leopoldsburg to Leopoldsburg is 3,688.12 miles which is equal to 5,935.46 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Leopoldsburg, Arr. Hasselt, Belgium