Distance from Secaucus to La Puebla de Cazalla
The shortest distance (air line) between Secaucus and La Puebla de Cazalla is 3,603.14 mi (5,798.70 km).
How far is Secaucus from La Puebla de Cazalla
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 08:28 (17.11.2025)
La Puebla de Cazalla is located in Sevilla, Spain within 37° 13' 19.92" N -6° 41' 15" W (37.2222, -5.3125) coordinates. The local time in La Puebla de Cazalla is 14:28 (17.11.2025)
The calculated flying distance from La Puebla de Cazalla to La Puebla de Cazalla is 3,603.14 miles which is equal to 5,798.70 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
La Puebla de Cazalla, Sevilla, Spain