Distance from Secaucus to Konstantynow Lodzki
The shortest distance (air line) between Secaucus and Konstantynow Lodzki is 4,213.15 mi (6,780.41 km).
How far is Secaucus from Konstantynow Lodzki
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 08:29 (12.11.2025)
Konstantynow Lodzki is located in Łódzki, Poland within 51° 45' 0" N 19° 19' 59.88" E (51.7500, 19.3333) coordinates. The local time in Konstantynow Lodzki is 14:29 (12.11.2025)
The calculated flying distance from Konstantynow Lodzki to Konstantynow Lodzki is 4,213.15 miles which is equal to 6,780.41 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Konstantynow Lodzki, Łódzki, Poland