Distance from Secaucus to Jastrzebie-Zdroj
The shortest distance (air line) between Secaucus and Jastrzebie-Zdroj is 4,247.84 mi (6,836.23 km).
How far is Secaucus from Jastrzebie-Zdroj
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 06:59 (12.11.2025)
Jastrzebie-Zdroj is located in Rybnicki, Poland within 49° 57' 0" N 18° 34' 59.88" E (49.9500, 18.5833) coordinates. The local time in Jastrzebie-Zdroj is 12:59 (12.11.2025)
The calculated flying distance from Jastrzebie-Zdroj to Jastrzebie-Zdroj is 4,247.84 miles which is equal to 6,836.23 km.
Secaucus, New Jersey, United States
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Jastrzebie-Zdroj, Rybnicki, Poland