Distance from Secaucus to Civitanova Marche
The shortest distance (air line) between Secaucus and Civitanova Marche is 4,285.37 mi (6,896.64 km).
How far is Secaucus from Civitanova Marche
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 23:19 (25.08.2025)
Civitanova Marche is located in Macerata, Italy within 43° 17' 60" N 13° 43' 59.88" E (43.3000, 13.7333) coordinates. The local time in Civitanova Marche is 05:19 (26.08.2025)
The calculated flying distance from Civitanova Marche to Civitanova Marche is 4,285.37 miles which is equal to 6,896.64 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Civitanova Marche, Macerata, Italy