Distance from Secaucus to Boguszow-Gorce
The shortest distance (air line) between Secaucus and Boguszow-Gorce is 4,128.63 mi (6,644.39 km).
How far is Secaucus from Boguszow-Gorce
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 22:42 (12.11.2025)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 04:42 (13.11.2025)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,128.63 miles which is equal to 6,644.39 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Boguszow-Gorce, Wałbrzyski, Poland