Distance from Secaucus to Badhoevedorp
The shortest distance (air line) between Secaucus and Badhoevedorp is 3,638.58 mi (5,855.72 km).
How far is Secaucus from Badhoevedorp
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 23:07 (10.11.2025)
Badhoevedorp is located in Groot-Amsterdam, Netherlands within 52° 19' 59.88" N 4° 46' 59.88" E (52.3333, 4.7833) coordinates. The local time in Badhoevedorp is 05:07 (11.11.2025)
The calculated flying distance from Badhoevedorp to Badhoevedorp is 3,638.58 miles which is equal to 5,855.72 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Badhoevedorp, Groot-Amsterdam, Netherlands