Distance from Secaucus to Amsterdam
The shortest distance (air line) between Secaucus and Amsterdam is 3,641.95 mi (5,861.15 km).
How far is Secaucus from Amsterdam
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 16:02 (10.11.2025)
Amsterdam is located in Groot-Amsterdam, Netherlands within 52° 22' 22.08" N 4° 53' 36.96" E (52.3728, 4.8936) coordinates. The local time in Amsterdam is 22:02 (10.11.2025)
The calculated flying distance from Amsterdam to Amsterdam is 3,641.95 miles which is equal to 5,861.15 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Amsterdam, Groot-Amsterdam, Netherlands