Distance from Secaucus to Aleksandrovac
The shortest distance (air line) between Secaucus and Aleksandrovac is 4,588.38 mi (7,384.28 km).
How far is Secaucus from Aleksandrovac
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 00:00 (16.11.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 06:00 (16.11.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,588.38 miles which is equal to 7,384.28 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Aleksandrovac, Rasinska oblast, Serbia