Distance from Secaucus to Alblasserdam
The shortest distance (air line) between Secaucus and Alblasserdam is 3,645.42 mi (5,866.74 km).
How far is Secaucus from Alblasserdam
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 13:06 (10.11.2025)
Alblasserdam is located in Zuidoost-Zuid-Holland, Netherlands within 51° 52' 12.72" N 4° 40' 0.12" E (51.8702, 4.6667) coordinates. The local time in Alblasserdam is 19:06 (10.11.2025)
The calculated flying distance from Alblasserdam to Alblasserdam is 3,645.42 miles which is equal to 5,866.74 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Alblasserdam, Zuidoost-Zuid-Holland, Netherlands