Distance from Searcy to Boortmeerbeek
The shortest distance (air line) between Searcy and Boortmeerbeek is 4,624.26 mi (7,442.03 km).
How far is Searcy from Boortmeerbeek
Searcy is located in Arkansas, United States within 35° 14' 30.48" N -92° 15' 53.64" W (35.2418, -91.7351) coordinates. The local time in Searcy is 02:55 (30.07.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 09:55 (30.07.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,624.26 miles which is equal to 7,442.03 km.
Searcy, Arkansas, United States
Related Distances from Searcy
Boortmeerbeek, Arr. Leuven, Belgium