Distance from Schaesberg to Waldshut-Tiengen
The shortest distance (air line) between Schaesberg and Waldshut-Tiengen is 247.12 mi (397.70 km).
How far is Schaesberg from Waldshut-Tiengen
Schaesberg is located in Zuid-Limburg, Netherlands within 50° 53' 60" N 6° 1' 0.12" E (50.9000, 6.0167) coordinates. The local time in Schaesberg is 00:00 (17.08.2025)
Waldshut-Tiengen is located in Waldshut, Germany within 47° 37' 23.16" N 8° 12' 51.84" E (47.6231, 8.2144) coordinates. The local time in Waldshut-Tiengen is 00:00 (17.08.2025)
The calculated flying distance from Waldshut-Tiengen to Waldshut-Tiengen is 247.12 miles which is equal to 397.70 km.
Schaesberg, Zuid-Limburg, Netherlands
Related Distances from Schaesberg
Waldshut-Tiengen, Waldshut, Germany