Distance from Savigny-le-Temple to Alexandroupoli
The shortest distance (air line) between Savigny-le-Temple and Alexandroupoli is 1,255.22 mi (2,020.08 km).
How far is Savigny-le-Temple from Alexandroupoli
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 00:01 (13.11.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 01:01 (13.11.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,255.22 miles which is equal to 2,020.08 km.
Savigny-le-Temple, Seine-et-Marne, France