Distance from Savage to Wallenhorst
The shortest distance (air line) between Savage and Wallenhorst is 4,273.05 mi (6,876.81 km).
How far is Savage from Wallenhorst
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 14:24 (27.08.2025)
Wallenhorst is located in Osnabrück; Landkreis, Germany within 52° 21' 0" N 8° 1' 0.12" E (52.3500, 8.0167) coordinates. The local time in Wallenhorst is 21:24 (27.08.2025)
The calculated flying distance from Wallenhorst to Wallenhorst is 4,273.05 miles which is equal to 6,876.81 km.
Savage, Minnesota, United States
Related Distances from Savage
Wallenhorst, Osnabrück; Landkreis, Germany