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      Distance from Savage to Villanueva de la Serena

      The shortest distance (air line) between Savage and Villanueva de la Serena is 4,298.25 mi (6,917.36 km).

      How far is Savage from Villanueva de la Serena

      Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 04:58 (18.11.2025)

      Villanueva de la Serena is located in Badajoz, Spain within 38° 58' 0.12" N -6° 12' 0" W (38.9667, -5.8000) coordinates. The local time in Villanueva de la Serena is 11:58 (18.11.2025)

      The calculated flying distance from Villanueva de la Serena to Villanueva de la Serena is 4,298.25 miles which is equal to 6,917.36 km.

      Savage, Minnesota, United States

      Related Distances from Savage

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      Savage to Washington (District of Columbia)931.35 mi (1,498.86 km)
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      Savage to Brooklyn (New York)1,022.91 mi (1,646.21 km)
      Savage to New York (New York)1,022.94 mi (1,646.26 km)
      Savage to Queens (New York)1,027.66 mi (1,653.85 km)
      Savage to Houston (Texas)1,040.11 mi (1,673.89 km)
      Savage to Boston (Massachusetts)1,124.85 mi (1,810.27 km)
      Savage to Phoenix (Arizona)1,261.01 mi (2,029.40 km)
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      Savage to Riverside (California)1,477.40 mi (2,377.65 km)
      Savage to Miami (Florida)1,501.70 mi (2,416.75 km)
      Savage to San Diego (California)1,512.96 mi (2,434.87 km)
      Savage to Los Angeles (California)1,516.37 mi (2,440.37 km)
      Savage to San Francisco (California)1,576.32 mi (2,536.85 km)
      Savage to Minneapolis (Minnesota)15.18 mi (24.43 km)
      Savage to Chicago (Illinois)349.30 mi (562.15 km)
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      Villanueva de la Serena, Badajoz, Spain

      Related Distances to Villanueva de la Serena