Distance from Savage to Vetraz-Monthoux
The shortest distance (air line) between Savage and Vetraz-Monthoux is 4,477.20 mi (7,205.36 km).
How far is Savage from Vetraz-Monthoux
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 15:08 (11.08.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 22:08 (11.08.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 4,477.20 miles which is equal to 7,205.36 km.
Savage, Minnesota, United States
Related Distances from Savage
Vetraz-Monthoux, Haute-Savoie, France