Distance from Savage to Tomaszow Lubelski
The shortest distance (air line) between Savage and Tomaszow Lubelski is 4,848.61 mi (7,803.08 km).
How far is Savage from Tomaszow Lubelski
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 21:16 (12.11.2025)
Tomaszow Lubelski is located in Chełmsko-zamojski, Poland within 50° 27' 0" N 23° 25' 0.12" E (50.4500, 23.4167) coordinates. The local time in Tomaszow Lubelski is 04:16 (13.11.2025)
The calculated flying distance from Tomaszow Lubelski to Tomaszow Lubelski is 4,848.61 miles which is equal to 7,803.08 km.
Savage, Minnesota, United States
Related Distances from Savage
Tomaszow Lubelski, Chełmsko-zamojski, Poland