Distance from Savage to Sokolow Podlaski
The shortest distance (air line) between Savage and Sokolow Podlaski is 4,715.77 mi (7,589.29 km).
How far is Savage from Sokolow Podlaski
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 19:33 (11.11.2025)
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 02:33 (12.11.2025)
The calculated flying distance from Sokolow Podlaski to Sokolow Podlaski is 4,715.77 miles which is equal to 7,589.29 km.
Savage, Minnesota, United States
Related Distances from Savage
Sokolow Podlaski, Siedlecki, Poland