Distance from Savage to Sendenhorst
The shortest distance (air line) between Savage and Sendenhorst is 4,288.21 mi (6,901.20 km).
How far is Savage from Sendenhorst
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 07:10 (25.08.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 14:10 (25.08.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 4,288.21 miles which is equal to 6,901.20 km.
Savage, Minnesota, United States
Related Distances from Savage
Sendenhorst, Warendorf, Germany