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      Distance from Savage to San Agustin de Guadalix

      The shortest distance (air line) between Savage and San Agustin de Guadalix is 4,320.40 mi (6,953.01 km).

      How far is Savage from San Agustin de Guadalix

      Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 06:15 (17.11.2025)

      San Agustin de Guadalix is located in Madrid, Spain within 40° 40' 41.16" N -4° 23' 6" W (40.6781, -3.6150) coordinates. The local time in San Agustin de Guadalix is 13:15 (17.11.2025)

      The calculated flying distance from San Agustin de Guadalix to San Agustin de Guadalix is 4,320.40 miles which is equal to 6,953.01 km.

      Savage, Minnesota, United States

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      San Agustin de Guadalix, Madrid, Spain

      Related Distances to San Agustin de Guadalix