Distance from Savage to Radzyn Podlaski
The shortest distance (air line) between Savage and Radzyn Podlaski is 4,757.67 mi (7,656.73 km).
How far is Savage from Radzyn Podlaski
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 05:00 (12.11.2025)
Radzyn Podlaski is located in Bialski, Poland within 51° 46' 58.08" N 22° 37' 27.12" E (51.7828, 22.6242) coordinates. The local time in Radzyn Podlaski is 12:00 (12.11.2025)
The calculated flying distance from Radzyn Podlaski to Radzyn Podlaski is 4,757.67 miles which is equal to 7,656.73 km.
Savage, Minnesota, United States
Related Distances from Savage
Radzyn Podlaski, Bialski, Poland