Distance from Savage to Padinska Skela
The shortest distance (air line) between Savage and Padinska Skela is 5,034.44 mi (8,102.15 km).
How far is Savage from Padinska Skela
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 12:16 (14.11.2025)
Padinska Skela is located in City of Belgrade, Serbia within 44° 57' 0" N 20° 25' 59.88" E (44.9500, 20.4333) coordinates. The local time in Padinska Skela is 19:16 (14.11.2025)
The calculated flying distance from Padinska Skela to Padinska Skela is 5,034.44 miles which is equal to 8,102.15 km.
Savage, Minnesota, United States
Related Distances from Savage
Padinska Skela, City of Belgrade, Serbia