Distance from Savage to Ozarow Mazowiecki
The shortest distance (air line) between Savage and Ozarow Mazowiecki is 4,682.32 mi (7,535.47 km).
How far is Savage from Ozarow Mazowiecki
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 12:33 (11.11.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 19:33 (11.11.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 4,682.32 miles which is equal to 7,535.47 km.
Savage, Minnesota, United States
Related Distances from Savage
Ozarow Mazowiecki, Warszawski zachodni, Poland