Distance from Savage to Montceau-les-Mines
The shortest distance (air line) between Savage and Montceau-les-Mines is 4,385.82 mi (7,058.30 km).
How far is Savage from Montceau-les-Mines
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 22:32 (09.08.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 05:32 (10.08.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,385.82 miles which is equal to 7,058.30 km.
Savage, Minnesota, United States
Related Distances from Savage
Montceau-les-Mines, Saône-et-Loire, France