Distance from Savage to Lidzbark Warminski
The shortest distance (air line) between Savage and Lidzbark Warminski is 4,582.80 mi (7,375.31 km).
How far is Savage from Lidzbark Warminski
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 16:57 (11.11.2025)
Lidzbark Warminski is located in Olsztyński, Poland within 54° 7' 0.12" N 20° 34' 59.88" E (54.1167, 20.5833) coordinates. The local time in Lidzbark Warminski is 23:57 (11.11.2025)
The calculated flying distance from Lidzbark Warminski to Lidzbark Warminski is 4,582.80 miles which is equal to 7,375.31 km.
Savage, Minnesota, United States
Related Distances from Savage
Lidzbark Warminski, Olsztyński, Poland