Distance from Savage to La Puebla del Rio
The shortest distance (air line) between Savage and La Puebla del Rio is 4,358.06 mi (7,013.61 km).
How far is Savage from La Puebla del Rio
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 19:30 (16.11.2025)
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 02:30 (17.11.2025)
The calculated flying distance from La Puebla del Rio to La Puebla del Rio is 4,358.06 miles which is equal to 7,013.61 km.
Savage, Minnesota, United States
Related Distances from Savage
La Puebla del Rio, Sevilla, Spain