Distance from Savage to La Puebla de Cazalla
The shortest distance (air line) between Savage and La Puebla de Cazalla is 4,392.14 mi (7,068.46 km).
How far is Savage from La Puebla de Cazalla
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 18:41 (16.11.2025)
La Puebla de Cazalla is located in Sevilla, Spain within 37° 13' 19.92" N -6° 41' 15" W (37.2222, -5.3125) coordinates. The local time in La Puebla de Cazalla is 01:41 (17.11.2025)
The calculated flying distance from La Puebla de Cazalla to La Puebla de Cazalla is 4,392.14 miles which is equal to 7,068.46 km.
Savage, Minnesota, United States
Related Distances from Savage
La Puebla de Cazalla, Sevilla, Spain