Distance from Savage to Janow Lubelski
The shortest distance (air line) between Savage and Janow Lubelski is 4,805.31 mi (7,733.40 km).
How far is Savage from Janow Lubelski
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 23:15 (11.11.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 06:15 (12.11.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,805.31 miles which is equal to 7,733.40 km.
Savage, Minnesota, United States
Related Distances from Savage
Janow Lubelski, Puławski, Poland