Distance from Savage to Fontainebleau
The shortest distance (air line) between Savage and Fontainebleau is 4,250.99 mi (6,841.30 km).
How far is Savage from Fontainebleau
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 22:16 (07.08.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 05:16 (08.08.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 4,250.99 miles which is equal to 6,841.30 km.
Savage, Minnesota, United States
Related Distances from Savage
Fontainebleau, Seine-et-Marne, France