Distance from Savage to Bad Sooden-Allendorf
The shortest distance (air line) between Savage and Bad Sooden-Allendorf is 4,384.68 mi (7,056.46 km).
How far is Savage from Bad Sooden-Allendorf
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 12:19 (12.08.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 19:19 (12.08.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,384.68 miles which is equal to 7,056.46 km.
Savage, Minnesota, United States
Related Distances from Savage
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany