Distance from Savage to Bad Sassendorf
The shortest distance (air line) between Savage and Bad Sassendorf is 4,310.74 mi (6,937.47 km).
How far is Savage from Bad Sassendorf
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 09:37 (12.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 16:37 (12.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,310.74 miles which is equal to 6,937.47 km.
Savage, Minnesota, United States
Related Distances from Savage
Bad Sassendorf, Soest, Germany