Distance from Savage to Bad Oeynhausen
The shortest distance (air line) between Savage and Bad Oeynhausen is 4,305.50 mi (6,929.04 km).
How far is Savage from Bad Oeynhausen
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 06:03 (12.08.2025)
Bad Oeynhausen is located in Minden-Lübbecke, Germany within 52° 12' 0" N 8° 48' 0" E (52.2000, 8.8000) coordinates. The local time in Bad Oeynhausen is 13:03 (12.08.2025)
The calculated flying distance from Bad Oeynhausen to Bad Oeynhausen is 4,305.50 miles which is equal to 6,929.04 km.
Savage, Minnesota, United States
Related Distances from Savage
Bad Oeynhausen, Minden-Lübbecke, Germany